The basic characteristics of thermistor1

Thermistor belongs to a kind of sensitive element, is easy to use, small volume, good stability, high sensitivity, a variety of advantages, has a certain application in multiple industries. Thermistor itself also requires the user to understand the characteristics of, this project is for everybody detailed introduction of the characteristics of the thermal resistor, the hope can help to you.

the resistance of the thermistor - Temperature characteristic can be approximately expressed in the type: R = R0exp { B( 1 t - 1 t0) } Temperature T (R: K) The resistance value, Ro: temperature T0, ( K) At the time of the resistance, BB value, * T ( K) =t( ºC) + 27315. In fact, B value of the thermistor is not constant, the change vary with material and size, the largest even up to 5 ° C k. So in the larger temperature range application type 1, will and there is a certain error between the measured values. Here, if use the B value in type 1 type 2 as a function of temperature computation, can be reduced and the error between the measured values, can be considered approximately equal.

BT = CT2 + DT + E, the type, C, D, E, is constant. In addition, due to the different production conditions by fluctuations in the value of B causes constant E changes, but the constant C, D unchanged. Therefore, to explore the influence of B value fluctuation quantity, only need to consider the constant E can. The calculation of the constant C, D, E, constant C, D, E by 4 PM ( Temperature, electrical resistance) Data ( T0,R0) ( T1, R1) ( T2,R2) and( T3, R3) And through the calculation of type 3 ~ 6. First by the style 3 according to the T0 and T1, T2, T3, resistance and the B1, B2, B3, and then plug in the following style.

resistance calculation example: try according to resistance - Temperature characteristic table, 25 ° C when resistance is 5 ( kΩ) , B value deviation of 50 ( K) Thermistor in 10 ° C ~ 30 ° C resistance value. Step ( 1) According to the resistance - Constant temperature characteristic table, o, C, D, E. = 25 + 27315 t1 = 10 + 27315 t2 = 20 + 27315 t3 = 30 + 27315 ( 2) In BT = CT2 + DT + E + 50, BT. ( 3) Numerical generation into R = 5 exp { ( BT1T - 129815). } , R. * T10 + 27315 ~ 30 + 27315。

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key words: thermal resistance, thermocouple, thermal resistance, platinum resistance, PT100, PT1000, pressure sensor and digital temperature sensor